Answer by rob for Why is the uncertainty principle not $\sigma_A^2...
Griffiths' formulation makes it explicit that operators which commute are not restricted by the uncertainty principle. Your boxed expression obscures this physical and mathematical insight.
View ArticleAnswer by Mostafa for Why is the uncertainty principle not $\sigma_A^2...
The most correct relation is the following general relation, that actually contains both terms.If you omit the inequality $(|z|^2\geq(Im(z))^2)$ from the derivation, the next steps toward the...
View ArticleWhy is the uncertainty principle not $\sigma_A^2 \sigma_B^2\geq(\langle A...
In Griffiths' QM, he uses two inequalities (here numbered as $(1)$ and $(2)$) to prove the following general uncertainty principle:$$\sigma_A^2 \sigma_B^2\geq\left(\frac{1}{2i}\langle [\hat A ,\hat...
View Article
More Pages to Explore .....
